olymmath

IrMO 2016

Irish Mathematical Olympiad 2016.

Paper 1

Problem 1

  • Paper 1

If the three-digit number ABCABC is divisible by 2727 , prove that the three-digit numbers BCABCA and CABCAB are also divisible by 2727 .

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Problem 2

  • Paper 1

In triangle ABCABC we have ∣AB∣≠∣AC∣|AB| \ne |AC| . The bisectors of ∠ABC\angle ABC and ∠ACB\angle ACB meet ACAC and ABAB at EE and FF , respectively, and intersect at I. If ∣EI∣=∣FI∣|EI| = |FI| find the measure of ∠BAC\angle BAC .

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Problem 3

  • Paper 1

Do there exist four polynomials P1(x),P2(x),P3(x),P4(x)P_1(x), P_2(x), P_3(x), P_4(x) with real coefficients, such that the sum of any three of them always has a real root, but the sum of any two of them has no real root?

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Problem 4

  • Paper 1

Let ABCABC be a triangle with ∣AC∣≠∣BC∣|AC| \ne |BC| . Let PP and QQ be the intersection points of the line ABAB with the internal and external angle bisectors at CC , so that PP is between AA and BB . Prove that if MM is any point on the circle with diameter PQPQ , then ∠AMP=∠BMP\angle AMP = \angle BMP .

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Problem 5

  • Paper 1

Let a1,a2,...,ama_1, a_2, ..., a_m be positive integers, none of which is equal to 1010 , such that a1+a2+...+am=10ma_1 + a_2 + ...+ a_m = 10m . Prove that (a1a2a3⋅...⋅am)1/m≤311(a_1a_2a_3 \cdot ...\cdot a_m)^{1/m} \le 3\sqrt{11} .

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Paper 2

Problem 6

  • Paper 2

Triangle ABCABC has sides a=∣BC∣>b=∣AC∣a = |BC| > b = |AC| . The points KK and HH on the segment BCBC satisfy ∣CH∣=(a+b)/3|CH| = (a + b)/3 and ∣CK∣=(a−b)/3|CK| = (a - b)/3 . If GG is the centroid of triangle ABCABC , prove that ∠KGH=90o\angle KGH = 90^o .

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Problem 7

  • Paper 2

A rectangular array of positive integers has 44 rows. The sum of the entries in each column is 2020 . Within each row, all entries are distinct. What is the maximum possible number of columns?

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Problem 8

  • Paper 2

Suppose a,b,ca, b, c are real numbers such that abc≠0abc \ne 0 . Determine x,y,zx, y, z in terms of a,b,ca, b, c such that bz+cy=a,cx+az=b,ay+bx=cbz + cy = a, cx + az = b, ay + bx = c . Prove also that 1−x2a2=1−y2b2=1−z2c2\frac{1 - x^2}{a^2} = \frac{1 - y^2}{b^2} = \frac{1 - z^2}{c^2} .

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Problem 9

  • Paper 2

Show that the number a3a^3 where a=25112523−523−10633+12512523+523+10633a=\frac{251}{ \frac{1}{\sqrt[3]{252}-5\sqrt[3]{2}}-10\sqrt[3]{63}}+\frac{1}{\frac{251}{\sqrt[3]{252}+5\sqrt[3]{2}}+10\sqrt[3]{63}} is an integer and find its value

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Problem 10

  • Paper 2

Let AEAE be a diameter of the circumcircle of triangle ABCABC . Join EE to the orthocentre, HH , of △ABC\triangle ABC and extend EHEH to meet the circle again at DD . Prove that the nine point circle of △ABC\triangle ABC passes through the midpoint of HDHD .

Note. The nine point circle of a triangle is a circle that passes through the midpoints of the sides, the feet of the altitudes and the midpoints of the line segments that join the orthocentre to the vertices.

Answer, solutions and source