olymmath

IrMO 2016 Problem 5

  • Paper 1

Let a1,a2,...,ama_1, a_2, ..., a_m be positive integers, none of which is equal to 1010 , such that a1+a2+...+am=10ma_1 + a_2 + ...+ a_m = 10m . Prove that (a1a2a3⋅...⋅am)1/m≤311(a_1a_2a_3 \cdot ...\cdot a_m)^{1/m} \le 3\sqrt{11} .

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator ie-irmo/2016/p5 · Tag ZZJBV22JKW · Edit this page on GitHub · Keys: j next, k previous