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HMMT 2022 A7

  • Algebra and Number Theory
  • Answer

Let (x1,y1),(x2,y2),(x3,y3),(x4,y4)\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right),\left(x_{3}, y_{3}\right),\left(x_{4}, y_{4}\right), and (x5,y5)\left(x_{5}, y_{5}\right) be the vertices of a regular pentagon centered at (0,0)(0,0). Compute the product of all positive integers kk such that the equality

x1k+x2k+x3k+x4k+x5k=y1k+y2k+y3k+y4k+y5kx_{1}^{k}+x_{2}^{k}+x_{3}^{k}+x_{4}^{k}+x_{5}^{k}=y_{1}^{k}+y_{2}^{k}+y_{3}^{k}+y_{4}^{k}+y_{5}^{k}

must hold for all possible choices of the pentagon.

Dataset text NuminaMath olympiads. Quoted with source.

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