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HMMT 2015 A2

  • Algebra
  • Answer

The fraction 12015\frac{1}{2015} has a unique "(restricted) partial fraction decomposition" of the form

12015=a5+b13+c31\frac{1}{2015}=\frac{a}{5}+\frac{b}{13}+\frac{c}{31}

where a,b,ca, b, c are integers with 0≤a<50 \leq a<5 and 0≤b<130 \leq b<13. Find a+ba+b.

Dataset text NuminaMath olympiads. Quoted with source.

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