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HMMT 2015 A1

  • Algebra
  • Answer

Let QQ be a polynomial

Q(x)=a0+a1x+⋯+anxnQ(x)=a_{0}+a_{1} x+\cdots+a_{n} x^{n}

where a0,…,ana_{0}, \ldots, a_{n} are nonnegative integers. Given that Q(1)=4Q(1)=4 and Q(5)=152Q(5)=152, find Q(6)Q(6).

Dataset text NuminaMath olympiads. Quoted with source.

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