olymmath

OFM 2023

Olympiade Francophone de Mathématiques 2023.

Junior

J1

  • Junior

Let u0,u1,u2,…u_0, u_1, u_2, \ldots be integers such that u0=100u_0 = 100 ; uk+2⩾2+uku_{k+2} \geqslant 2 + u_k for all k⩾0k \geqslant 0 ; and uℓ+5⩽5+uℓu_{\ell+5} \leqslant 5 + u_\ell for all ℓ⩾0\ell \geqslant 0 . Find all possible values for the integer u2023u_{2023} .

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J2

  • Junior

On her blackboard, Alice has written nn integers strictly greater than 11 . Then, she can, as often as she likes, erase two numbers aa and bb such that a≠ba \neq b , and replace them with qq and q2q^2 , where qq is the product of the prime factors of abab (each prime factor is counted only once). For instance, if Alice erases the numbers 44 and 66 , the prime factors of ab=23×3ab = 2^3 \times 3 and 22 and 33 , and Alice writes q=6q = 6 and q2=36q^2 =36 . Prove that, after some time, and whatever Alice's strategy is, the list of numbers written on the blackboard will never change anymore.

Note: The order of the numbers of the list is not important.

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J3

  • Junior

Let Γ\Gamma and Γ′\Gamma' be two circles with centres OO and O′O' , such that OO belongs to Γ′\Gamma' . Let MM be a point on Γ′\Gamma' , outside of Γ\Gamma . The tangents to Γ\Gamma that go through MM touch Γ\Gamma in two points AA and BB , and cross Γ′\Gamma' again in two points CC and DD . Finally, let EE be the crossing point of the lines ABAB and CDCD . Prove that the circumcircles of the triangles CEO′CEO' and DEO′DEO' are tangent to Γ′\Gamma' .

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Senior

S1

  • Senior

Let P(X)=anXn+an−1Xn−1+⋯+a1X+a0P(X) = a_n X^n + a_{n-1} X^{n-1} + \cdots + a_1 X + a_0 be a polynomial with real coefficients such that 0⩽ai⩽a00 \leqslant a_i \leqslant a_0 for i=1,2,…,ni = 1, 2, \ldots, n . Prove that, if P(X)2=b2nX2n+b2n−1X2n−1+⋯+bn+1Xn+1+⋯+b1X+b0P(X)^2 = b_{2n} X^{2n} + b_{2n-1} X^{2n-1} + \cdots + b_{n+1} X^{n+1} + \cdots + b_1 X + b_0 , then 4bn+1⩽P(1)24 b_{n+1} \leqslant P(1)^2 .

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S2

  • Senior

Let kk be a positive integer. Scrooge McDuck owns kk gold coins. He also owns infinitely many boxes B1,B2,B3,…B_1, B_2, B_3, \ldots Initially, bow B1B_1 contains one coin, and the k−1k-1 other coins are on McDuck's table, outside of every box. Then, Scrooge McDuck allows himself to do the following kind of operations, as many times as he likes:

  • if two consecutive boxes BiB_i and Bi+1B_{i+1} both contain a coin, McDuck can remove the coin contained in box Bi+1B_{i+1} and put it on his table;
  • if a box BiB_i contains a coin, the box Bi+1B_{i+1} is empty, and McDuck still has at least one coin on his table, he can take such a coin and put it in box Bi+1B_{i+1} . As a function of kk , which are the integers nn for which Scrooge McDuck can put a coin in box BnB_n ?

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S3

  • Senior

Let ABCDABCD be a convex quadrilateral, with ∡ABC>90∘\measuredangle ABC > 90^\circ , ∡CDA>90∘\measuredangle CDA > 90^\circ and ∡DAB=∡BCD\measuredangle DAB = \measuredangle BCD . Let EE , FF and GG be the reflections of AA with respect to the lines BCBC , CDCD and DBDB . Finally, let the line BDBD meet the line segment AEAE at a point KK , and the line segment AFAF at a point LL . Prove that the circumcircles of the triangles BEKBEK and DFLDFL are tangent to each other at GG .

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S4

  • Senior

Do there exist integers aa and bb such that none of the numbers a,a+1,…,a+2023,b,b+1,…,b+2023a,a+1,\ldots,a+2023,b,b+1,\ldots,b+2023 divides any of the 40474047 other numbers, but a(a+1)(a+2)⋯(a+2023)a(a+1)(a+2)\cdots(a+2023) divides b(b+1)⋯(b+2023)b(b+1)\cdots(b+2023) ?

Answer, solutions and source