olymmath

CN-TST 2021 Problem 11

  • Test 2

Let nn be a positive integer and a1,a2,…a2n+1a_1,a_2,\ldots a_{2n+1} be positive reals. For k=1,2,…,2n+1k=1,2,\ldots ,2n+1 , denote bk=max⁡0≤m≤n(12m+1∑i=k−mk+mai)b_k = \max_{0\le m\le n}\left(\frac{1}{2m+1} \sum_{i=k-m}^{k+m} a_i \right) , where indices are taken modulo 2n+12n+1 . Prove that the number of indices kk satisfying bk≥1b_k\ge 1 does not exceed 2∑i=12n+1ai2\sum_{i=1}^{2n+1} a_i .

Dataset text AI-MO AoPS. Quoted with source.

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