olymmath

KöMaL 2017 B4905

    Let a1≥a2≥a3≥⋯≥a2n−1≥a2n≥0a_1 \ge a_2 \ge a_3 \ge \cdots \ge a_{2n-1} \ge a_{2n} \ge 0, and ∑i=12nai=1\sum_{i=1}^{2n} a_i = 1. Prove that a1a2+3a3a4+5a5a6+…+(2n−1)a2n−1a2n≤14.a_1 a_2 + 3 a_3 a_4 + 5 a_5 a_6 + \ldots + (2n-1) a_{2n-1} a_{2n} \le \frac{1}{4}. When will the equality hold?

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