Home Competitions AMC 12 2008a Problem 20
Triangle A B C ABC A B C has A C = 3 AC=3 A C = 3 , B C = 4 BC=4 B C = 4 , and A B = 5 AB=5 A B = 5 . Point D D D is on A B ‾ \overline{AB} A B , and C D ‾ \overline{CD} C D bisects the right angle. The inscribed circles of △ A D C \triangle ADC △ A D C and △ B C D \triangle BCD △ B C D have radii r a r_a r a and r b r_b r b , respectively. What is r a / r b r_a/r_b r a / r b ?
( A ) 1 28 ( 10 − 2 ) ( B ) 3 56 ( 10 − 2 ) ( C ) 1 14 ( 10 − 2 ) ( D ) 5 56 ( 10 − 2 ) ( E ) 3 28 ( 10 − 2 ) \mathrm{(A)}\ \frac{1}{28}\left(10-\sqrt{2}\right) \mathrm{(B)}\ \frac{3}{56}\left(10-\sqrt{2}\right) \mathrm{(C)}\ \frac{1}{14}\left(10-\sqrt{2}\right) \mathrm{(D)}\ \frac{5}{56}\left(10-\sqrt{2}\right)\\\mathrm{(E)}\ \frac{3}{28}\left(10-\sqrt{2}\right) ( A ) 28 1 ( 10 − 2 ) ( B ) 56 3 ( 10 − 2 ) ( C ) 14 1 ( 10 − 2 ) ( D ) 56 5 ( 10 − 2 ) ( E ) 28 3 ( 10 − 2 )
Dataset text AMC 12 2000 to 2025 . Quoted with source.
Show the answer
Solutions
No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.
Add a solution
Similar problems
These problems have the most words in common with this statement.
Locator amc12/2008a/p20 · Tag WCHYM0QVZ8 · Edit this page on GitHub · Keys: j next, k previous