olymmath

USAMO 1982 Problem 2

  • Day 1
  • Answer

Show that if m,nm, n are positive integers such that (xm+n+ym+n+zm+n)/(m+n)=(xm+ym+zm)/m(xn+yn+\left(x^{m+n}+y^{m+n}+z^{m+n}\right) /(m+n)=\left(x^{m}+y^{m}+z^{m}\right) / m\left(x^{n}+y^{n}+\right. zn)/n\left.\mathrm{z}^{\mathrm{n}}\right) / \mathrm{n} for all real x,y,z\mathrm{x}, \mathrm{y}, \mathrm{z} with sum 0 , then {m,n}={2,3}\{\mathrm{m}, \mathrm{n}\}=\{2,3\} or {2,5}\{2,5\}.

Dataset text NuminaMath olympiads. Quoted with source.

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{2,3} \text{ or } {2,5}

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