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AHSME 1991 Problem 20

    The sum of all real xx such that (2x−4)3+(4x−2)3=(4x+2x−6)3(2^x-4)^3+(4^x-2)^3=(4^x+2^x-6)^3 is (A) 32(B) 2(C) 52(D) 3(E) 72\textbf{(A) } \frac32 \textbf{(B) } 2 \textbf{(C) } \frac52 \textbf{(D) } 3 \textbf{(E) } \frac72

    Dataset text NuminaMath-1.5. Quoted with source.

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    \frac{7}{2}

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