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AHSME 1991 Problem 19

    Triangle ABCABC has a right angle at C,AC=3C, AC=3 and BC=4BC=4. Triangle ABDABD has a right angle at AA and AD=12AD=12. Points CC and DD are on opposite sides of AB‾\overline{AB}. The line through DD parallel to AC‾\overline{AC} meets CB‾\overline{CB} extended at EE. If DEDB=mn,\frac{DE}{DB}=\frac{m}{n}, where mm and nn are relatively prime positive integers, then m+n=m+n= (A) 25(B) 128(C) 153(D) 243(E) 256\text{(A) } 25 \text{(B) } 128 \text{(C) } 153 \text{(D) } 243 \text{(E) } 256

    Dataset text NuminaMath-1.5. Quoted with source.

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    128

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