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AHSME 1983 Problem 8

    Let f(x)=x+1x−1f(x) = \frac{x+1}{x-1}. Then for x2≠1,f(−x)x^2 \neq 1, f(-x) is (A) 1f(x)(B) −f(x)(C) 1f(−x)(D) −f(−x)(E) f(x)\textbf{(A)}\ \frac{1}{f(x)} \textbf{(B)}\ -f(x) \textbf{(C)}\ \frac{1}{f(-x)} \textbf{(D)}\ -f(-x) \textbf{(E)}\ f(x)

    Dataset text NuminaMath-1.5. Quoted with source.

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