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AHSME 1979 Problem 8

    Find the area of the smallest region bounded by the graphs of y=∣x∣y=|x| and x2+y2=4x^2+y^2=4. (A) π4(B) 3π4(C) π(D) 3π2(E) 2π\textbf{(A) }\frac{\pi}{4} \textbf{(B) }\frac{3\pi}{4} \textbf{(C) }\pi \textbf{(D) }\frac{3\pi}{2} \textbf{(E) }2\pi

    Dataset text NuminaMath-1.5. Quoted with source.

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