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AHSME 1991 Problem 2

    ∣3−π∣=|3-\pi|= (A) 17(B) 0.14(C) 3−π(D) 3+π(E) π−3\textbf{(A)\ }\frac{1}{7} \textbf{(B)\ }0.14 \textbf{(C)\ }3-\pi \textbf{(D)\ }3+\pi \textbf{(E)\ }\pi-3

    Dataset text NuminaMath-1.5. Quoted with source.

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    \pi-3

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