AHSME 1962 Problem 16

Given rectangle $R_1$ with one side $2$ inches and area $12$ square inches. Rectangle $R_2$ with diagonal $15$ inches is similar to $R_1$. Expressed in square inches the area of $R_2$ is: $\textbf{(A)}\ \frac{9}2 \textbf{(B)}\ 36 \textbf{(C)}\ \frac{135}{2} \textbf{(D)}\ 9\sqrt{10} \textbf{(E)}\ \frac{27\sqrt{10}}{4}$