AHSME 1960 Problem 4

Each of two angles of a triangle is $60^{\circ}$ and the included side is $4$ inches. The area of the triangle, in square inches, is: $\textbf{(A)} 8\sqrt{3} \textbf{(B)} 8 \textbf{(C)} 4\sqrt{3} \textbf{(D)} 4 \textbf{(E)} 2\sqrt{3}$