AHSME 1960 Problem 7

Circle $I$ passes through the center of, and is tangent to, circle $II$. The area of circle $I$ is $4$ square inches. Then the area of circle $II$, in square inches, is: $\textbf{(A) }8 \textbf{(B) }8\sqrt{2} \textbf{(C) }8\sqrt{\pi} \textbf{(D) }16 \textbf{(E) }16\sqrt{2}$