Home Competitions AHSME 1961 Problem 35
The number 695 695 695 695 = a 1 + a 2 × 2 ! + a 3 × 3 ! + … a n × n ! 695=a_1+a_2\times2!+a_3\times3!+ \ldots a_n \times n! 695 = a 1 + a 2 × 2 ! + a 3 × 3 ! + … a n × n ! a 1 , a 2 , a 3 . . . a n a_1, a_2, a_3 ... a_n a 1 , a 2 , a 3 ... a n 0 ≤ a k ≤ k , 0 \le a_k \le k, 0 ≤ a k ≤ k , n ! n! n ! n ( n − 1 ) ( n − 2 ) . . .2 × 1 n(n-1)(n-2)...2 \times 1 n ( n − 1 ) ( n − 2 ) ...2 × 1 a 4 a_4 a 4 (A) 0 (B) 1 (C) 2 (D) 3 (E) 4 \textbf{(A)}\ 0 \textbf{(B)}\ 1 \textbf{(C)}\ 2 \textbf{(D)}\ 3 \textbf{(E)}\ 4 (A) 0 (B) 1 (C) 2 (D) 3 (E) 4
Dataset text NuminaMath-1.5 . Quoted with source.
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