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AHSME 1961 Problem 36

    In △ABC\triangle ABC the median from AA is given perpendicular to the median from BB. If BC=7BC=7 and AC=6AC=6, find the length of ABAB. (A) 4(B) 17(C) 4.25(D) 25(E) 4.5\textbf{(A)}\ 4 \textbf{(B)}\ \sqrt{17} \textbf{(C)}\ 4.25 \textbf{(D)}\ 2\sqrt{5} \textbf{(E)}\ 4.5

    Dataset text NuminaMath-1.5. Quoted with source.

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    \sqrt{17}

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