AHSME 1960 Problem 6

The circumference of a circle is $100$ inches. The side of a square inscribed in this circle, expressed in inches, is: $\textbf{(A) }\frac{25\sqrt{2}}{\pi} \textbf{(B) }\frac{50\sqrt{2}}{\pi} \textbf{(C) }\frac{100}{\pi} \textbf{(D) }\frac{100\sqrt{2}}{\pi} \textbf{(E) }50\sqrt{2}$