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AHSME 1960 Problem 14

    If aa and bb are real numbers, the equation 3x−5+a=bx+13x-5+a=bx+1 has a unique solution xx [The symbol a≠0a \neq 0 means that aa is different from zero]: (A) for all a and b(B) if a ≠2b(C) if a ≠6(D) if b ≠0(E) if b ≠3\text{(A) for all a and b} \text{(B) if a }\neq\text{2b} \text{(C) if a }\neq 6 \\ \text{(D) if b }\neq 0 \text{(E) if b }\neq 3

    Dataset text NuminaMath-1.5. Quoted with source.

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