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AHSME 1991 Problem 7

    If x=abx=\frac{a}{b}, a≠ba\neq b and b≠0b\neq 0, then a+ba−b=\frac{a+b}{a-b}= (A) xx+1\frac{x}{x+1} (B) x+1x−1\frac{x+1}{x-1} (C) 11 (D) x−1xx-\frac{1}{x} (E) x+1xx+\frac{1}{x}

    Dataset text NuminaMath-1.5. Quoted with source.

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