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AHSME 1952 Problem 24

    In the figure, it is given that angle C=90∘C = 90^{\circ}, AD‾=DB‾\overline{AD} = \overline{DB}, DE⊥ABDE \perp AB, AB‾=20\overline{AB} = 20, and AC‾=12\overline{AC} = 12. The area of quadrilateral ADECADEC is:

    (A) 75(B) 5812(C) 48(D) 3712(E) none of these\textbf{(A)}\ 75 \textbf{(B)}\ 58\frac{1}{2} \textbf{(C)}\ 48 \textbf{(D)}\ 37\frac{1}{2} \textbf{(E)}\ \text{none of these}

    Dataset text NuminaMath-1.5. Quoted with source.

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    58\frac{1}{2}

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