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AHSME 1952 Problem 23

    If x2−bxax−c=m−1m+1\frac{x^2-bx}{ax-c}=\frac{m-1}{m+1} has roots which are numerically equal but of opposite signs, the value of mm must be: (A)  a−ba+b(B)  a+ba−b(C)  c(D)  1c(E)  1\textbf{(A) \ }\frac{a-b}{a+b} \textbf{(B) \ }\frac{a+b}{a-b} \textbf{(C) \ }c \textbf{(D) \ }\frac{1}{c} \textbf{(E) \ }1

    Dataset text NuminaMath-1.5. Quoted with source.

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