olymmath

AMC 12 2013b Problem 19

  • Paper

In triangle ABCABC, AB=13AB=13, BC=14BC=14, and CA=15CA=15. Distinct points DD, EE, and FF lie on segments BC‾\overline{BC}, CA‾\overline{CA}, and DE‾\overline{DE}, respectively, such that AD‾⊥BC‾\overline{AD}\perp\overline{BC}, DE‾⊥AC‾\overline{DE}\perp\overline{AC}, and AF‾⊥BF‾\overline{AF}\perp\overline{BF}. The length of segment DF‾\overline{DF} can be written as mn\frac{m}{n}, where mm and nn are relatively prime positive integers. What is m+nm+n?

\textbf{(A)}\ 18 \textbf{(B)}\ 21 \textbf{(C)}\ 24 \textbf{(D)}\ 27 \textbf{(E)}\ 30

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

B

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2013b/p19 · Tag HCC44P1ZT1 · Edit this page on GitHub · Keys: j next, k previous