Home Competitions AHSME 1952 Problem 22
On hypotenuse A B AB A B of a right triangle A B C ABC A B C a second right triangle A B D ABD A B D is constructed with hypotenuse A B AB A B . If B C ‾ = 1 \overline{BC}=1 B C = 1 , A C ‾ = b \overline{AC}=b A C = b , and A D ‾ = 2 \overline{AD}=2 A D = 2 , then B D ‾ \overline{BD} B D equals:
(A) b 2 + 1 (B) b 2 − 3 (C) b 2 + 1 + 2 \textbf{(A) \ }\sqrt{b^2+1} \textbf{(B) \ }\sqrt{b^2-3} \textbf{(C) \ }\sqrt{b^2+1}+2 (A) b 2 + 1 (B) b 2 − 3 (C) b 2 + 1 + 2
(D) b 2 + 5 (E) b 2 + 3 \textbf{(D) \ }b^2+5 \textbf{(E) \ }\sqrt{b^2+3} (D) b 2 + 5 (E) b 2 + 3
Dataset text NuminaMath-1.5 . Quoted with source.
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