AHSME 1950 Problem 33

The number of circular pipes with an inside diameter of $1$ inch which will carry the same amount of water as a pipe with an inside diameter of $6$ inches is: $\textbf{(A)}\ 6\pi \textbf{(B)}\ 6 \textbf{(C)}\ 12 \textbf{(D)}\ 36 \textbf{(E)}\ 36\pi$