olymmath

VN-TST 2019 Problem 2

    For each positive integer nn , show that the polynomial: Pn(x)=∑k=0n2k(2n2k)xk(x−1)n−kP_n(x)=\sum _{k=0}^n2^k\binom{2n}{2k}x^k(x-1)^{n-k} has nn real roots.

    Dataset text AI-MO AoPS. Quoted with source.

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