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VN-TST 2005 Problem 5

    Let p∈P,p>3p\in \mathbb P,p>3 . Calcute:

    a) S=∑k=1p−12[2k2p]−2⋅[k2p]S=\sum_{k=1}^{\frac{p-1}{2}} \left[\frac{2k^2}{p}\right]-2 \cdot \left[\frac{k^2}{p}\right] if p≡1mod  4p\equiv 1 \mod 4

    b) T=∑k=1p−12[k2p]T=\sum_{k=1}^{\frac{p-1}{2}} \left[\frac{k^2}{p}\right] if p≡1mod  8p\equiv 1 \mod 8

    Dataset text AI-MO AoPS. Quoted with source.

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