TW-TST 1999 Problem 5

Let $AD,BE,CF$ be the altitudes of an acute triangle $ABC$ with $AB>AC$ . Line $EF$ meets $BC$ at $P$ , and line through $D$ parallel to $EF$ meets $AC$ and $AB$ at $Q$ and $R$ , respectively. Let $N$ be any poin on side $BC$ such that $\widehat{NQP}+\widehat{NRP}<180^{0}$ . Prove that $BN>CN$ .