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TUYMAADA 2020 J8

    In a horizontal strip 1×n1 \times n made of nn unit squares the vertices of all squares are marked. The strip is partitioned into parts by segments connecting marked points and not lying on the sides of the strip. The segments can not have common inner points; the upper end of each segment must be either above the lower end or further to the right. Prove that the number of all partitions is divisible by 2n2^n . (The partition where no segments are drawn, is counted too.)

    (E. Robeva, M. Sun)

    Dataset text AI-MO AoPS. Quoted with source.

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