olymmath

TUYMAADA 2019 Problem 1

    In a sequence a1,a2,..a_1, a_2, .. of real numbers the product a1a2a_1a_2 is negative, and to define ana_n for n>2n > 2 one pair (i,j)(i, j) is chosen among all the pairs (i,j),1≤i<j<n(i, j), 1 \le i < j < n , not chosen before, so that ai+aja_i +a_j has minimum absolute value, and then ana_n is set equal to ai+aja_i + a_j . Prove that ∣ai∣<1|a_i| < 1 for some ii .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator tuymaada/2019/p1 · Tag ME5V34SZCG · Edit this page on GitHub · Keys: j next, k previous