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KöMaL 2015 B4703

    Given that the absolute values of the numbers x1x_1, x2x_2, x3x_3, x4x_4, x5x_5, x6x_6 are at most 1, and their sum is 0, prove that 3∑i=151−xi2≤∑i=159−(xi+xi+1)2 .3\sum_{i=1}^{5} {\sqrt{1-x_i^2}} \le \sum_{i=1}^{5} {\sqrt{9-{(x_i+x_{i+1})}^2}}\,.

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