TUYMAADA 2014 S7

A parallelogram $ABCD$ is given. The excircle of triangle $\triangle{ABC}$ touches the sides $AB$ at $L$ and the extension of $BC$ at $K$ . The line $DK$ meets the diagonal $AC$ at point $X$ ; the line $BX$ meets the median $CC_1$ of trianlge $\triangle{ABC}$ at ${Y}$ . Prove that the line $YL$ , median $BB_1$ of triangle $\triangle{ABC}$ and its bisector $CC^\prime$ have a common point.

(A. Golovanov)