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TR-MO-R1 2023 Problem 11

    a1,a2,…,a31a_1, a_2, \ldots, a_{31} dizisi a1=131a_1 = \dfrac{1}{31} ve her n=1,2,…,30n = 1, 2, \ldots, 30 değeri için (n+2)an=nan+1(n+2)a_n = na_{n+1} olarak tanımlanmıştır. Buna göre, a1+a2+⋯+a31a_1 + a_2 + \cdots + a_{31} kaçtır?

    a) 176176 b) 179179 c) 181181 d) 187187 e) 192192

    Dataset text TÜBİTAK olympiad set, Matematik_2023_1.Asama_11. Quoted with source.

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