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TR-MO-R1 2018 Problem 7

    n1,n2,…,n2018n_1, n_2, \dots, n_{2018} tam sayılar olmak üzere,

    n12+n22+⋯+n20182+4036=3(n1+n2+⋯+n2018)n_1^2 + n_2^2 + \cdots + n_{2018}^2 + 4036 = 3(n_1 + n_2 + \cdots + n_{2018})

    eşitliği sağlanıyorsa, n12+n22+⋯+n20182n_1^2 + n_2^2 + \cdots + n_{2018}^2 toplamının alabileceği kaç farklı değer vardır?

    a) 1 b) 2019 c) 6055 d) 220182^{2018} e) Hiçbiri

    Official text Turkish Mathematical Olympiad, first round 2018 official paper, page 4. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/claude@2.1.318 (claude-opus-5-5). No person has checked it against the paper yet.

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