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SHARYGIN 2013 Problem 4

    Let ABCABC be a nonisosceles triangle. Point OO is its circumcenter, and point KK is the center of the circumcircle ww of triangle BCOBCO. The altitude of ABCABC from AA meets ww at a point PP. The line PKPK intersects the circumcircle of ABCABC at points EE and FF. Prove that one of the segments EPEP and FPFP is equal to the segment PAPA.

    Official text Sharygin Geometry Olympiad 2013 official paper, page 2. Quoted with source.

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