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BALTIC-WAY 2018 Problem 13

    The bisector of the angle AA of a triangle ABCA B C intersects BCB C in a point DD and intersects the circumcircle of the triangle ABCA B C in a point EE. Let K,L,MK, L, M and NN be the midpoints of the segments AB,BD,CDA B, B D, C D and ACA C, respectively. Let PP be the circumcenter of the triangle EKLE K L, and QQ be the circumcenter of the triangle EMNE M N. Prove that ∠PEQ=∠BAC\angle P E Q=\angle B A C.

    Dataset text NuminaMath olympiads. Quoted with source.

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