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SHARYGIN 2012 Problem 8

    Let BMBM be the median of right-angled triangle ABCABC (∠B=90∘\angle B = 90^\circ). The incircle of triangle ABMABM touches sides AB,AMAB, AM in points A1,A2A_1, A_2; points C1,C2C_1, C_2 are defined similarly. Prove that lines A1A2A_1A_2 and C1C2C_1C_2 meet on the bisector of angle ABCABC.

    Official text Sharygin Geometry Olympiad 2012 official paper, page 2. Quoted with source.

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