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SHARYGIN 2011 Problem 8

    The incircle of right-angled triangle ABCABC (∠B=90∘\angle B = 90^\circ) touches AB,BC,CAAB, BC, CA at points C1,A1,B1C_1, A_1, B_1 respectively. Points A2,C2A_2, C_2 are the reflections of B1B_1 in lines BC,ABBC, AB respectively. Prove that lines A1A2A_1A_2 and C1C2C_1C_2 meet on the median of triangle ABCABC.

    Official text Sharygin Geometry Olympiad 2011 official paper, page 2. Quoted with source.

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