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SHARYGIN 2011 Problem 5

    Given triangle ABCABC. The midperpendicular of side ABAB meets one of the remaining sides at point C′C'. Points A′A' and B′B' are defined similarly. For which original triangles triangle A′B′C′A'B'C' is regular?

    Official text Sharygin Geometry Olympiad 2011 official paper, page 2. Quoted with source.

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