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SHARYGIN 2011 Problem 3

    Let ABCABC be a triangle with ∠A=60∘\angle A = 60^\circ. The midperpendicular of segment ABAB meets line ACAC at point C1C_1. The midperpendicular of segment ACAC meets line ABAB at point B1B_1. Prove that line B1C1B_1C_1 touches the incircle of triangle ABCABC.

    Official text Sharygin Geometry Olympiad 2011 official paper, page 2. Quoted with source.

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