olymmath

SHARYGIN 2010 Problem 20

    The incircle of an acute-angled triangle ABCABC touches AB,BC,CAAB, BC, CA at points C1,A1,B1C_1, A_1, B_1 respectively. Points A2,B2A_2, B_2 are the midpoints of the segments B1C1,A1C1B_1C_1, A_1C_1 respectively. Let PP be a common point of the incircle and the line COCO, where OO is the circumcenter of ABCABC. Let also A′A' and B′B' be the second common points of PA2PA_2 and PB2PB_2 with the incircle. Prove that a common point of AA′AA' and BB′BB' lies on the altitude of the triangle dropped from the vertex CC.

    Official text Sharygin Geometry Olympiad 2010 official paper, page 3. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/local (GLM-OCR-8bit). No person has checked it against the paper yet.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator sharygin/2010/p20 · Tag J35MZHFMB2 · Edit this page on GitHub · Keys: j next, k previous