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SHARYGIN 2009 Problem 4

    Let PP and QQ be the common points of two circles. The ray with origin QQ reflects from the first circle in points A1,A2,…A_1, A_2, \ldots according to the rule “the angle of incidence is equal to the angle of reflection”. Another ray with origin QQ reflects from the second circle in the points B1,B2,…B_1, B_2, \ldots in the same manner. Points A1,B1A_1, B_1 and PP occurred to be collinear. Prove that all lines AiBiA_iB_i pass through PP.

    Official text Sharygin Geometry Olympiad 2009 official paper, page 2. Quoted with source.

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