olymmath

HMMT 2018 U26

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Let ABCA B C be a triangle with ∠A=18∘,∠B=36∘\angle A=18^{\circ}, \angle B=36^{\circ}. Let MM be the midpoint of AB,DA B, D a point on ray CMC M such that AB=AD;EA B=A D ; E a point on ray BCB C such that AB=BEA B=B E, and FF a point on ray ACA C such that AB=AFA B=A F. Find ∠FDE\angle F D E.

Dataset text NuminaMath olympiads. Quoted with source.

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