Home Competitions SE-SKOLORNAS 1972 Problem 4
SE-SKOLORNAS 1972 Problem 4
Put x = log 10 2 x = \log_{10} 2 x = log 10 2 , y = log 10 3 y = \log_{10} 3 y = log 10 3 . Then 15 < 16 15 < 16 15 < 16 implies 1 − x + y < 4 x 1 - x + y < 4x 1 − x + y < 4 x , so 1 + y < 5 x 1 + y < 5x 1 + y < 5 x .
Derive similar inequalities from 80 < 81 80 < 81 80 < 81 and 243 < 250 243 < 250 243 < 250 . Hence show that 0.47 < log 10 3 < 0.482. 0.47 < \log_{10} 3 < 0.482. 0.47 < log 10 3 < 0.482.
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