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SE-SKOLORNAS 1972 Problem 4

    Put x=log⁡102x = \log_{10} 2 , y=log⁡103y = \log_{10} 3 . Then 15<1615 < 16 implies 1−x+y<4x1 - x + y < 4x , so 1+y<5x1 + y < 5x . Derive similar inequalities from 80<8180 < 81 and 243<250243 < 250 . Hence show that 0.47<log⁡103<0.482.0.47 < \log_{10} 3 < 0.482.

    Dataset text AI-MO AoPS. Quoted with source.

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