olymmath

AIME 2003a Problem 4

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Given that log⁡10sin⁡x+log⁡10cos⁡x=−1\log_{10} \sin x + \log_{10} \cos x = -1 and that log⁡10(sin⁡x+cos⁡x)=12(log⁡10n−1),\log_{10} (\sin x + \cos x) = \frac{1}{2} (\log_{10} n - 1), find n.n.

Dataset text AIME 1983 to 2026. Quoted with source.

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