RU-ALLRUSSIAN 1977 Problem 14 The positive integers a1\mathbf{a}_1a1 , a2\mathbf{a}_2a2 , ..., am\mathbf{a}_{\mathrm{m}}am , b1\mathbf{b}_1b1 , b2\mathbf{b}_2b2 , ..., bn\mathbf{b}_{\mathrm{n}}bn satisfy: (a1+a2+…+am)=(b1+b2+…+bn)<mn(\mathbf{a}_1 + \mathbf{a}_2 + \ldots + \mathbf{a}_{\mathrm{m}}) = (\mathbf{b}_1 + \mathbf{b}_2 + \ldots + \mathbf{b}_{\mathrm{n}}) < \mathrm{mn}(a1+a2+…+am)=(b1+b2+…+bn)<mn . Show that we can delete some (but not all) of the numbers so that the sum of the remaining a's equals to the sum of the remaining b's. Dataset text NuminaMath olympiads. Quoted with source. Solutions No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label. Add a solution PreviousProblem 13 NextProblem 15 Locator ru-allrussian/1977/p14 · Tag Y84VK468GR · Edit this page on GitHub · Keys: j next, k previous