olymmath

RMM 2011

Romanian Master of Mathematics 2011.

Day 1

Problem 1

  • Day 1

Prove that there exist two functions

f,g:R→Rf, g: \mathbb{R} \rightarrow \mathbb{R}

such that f∘gf \circ g is strictly decreasing, while g∘fg \circ f is strictly increasing. (Poland) Andrzej KomisArsKi & Marcin Kuczma

Answer, solutions and source

Problem 2

  • Day 1

Determine all positive integers nn for which there exists a polynomial f(x)f(x) with real coefficients, with the following properties: (1) for each integer kk, the number f(k)f(k) is an integer if and only if kk is not divisible by nn; (2) the degree of ff is less than nn. (Hungary) GÉza Kós

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Problem 3

  • Day 1

A triangle ABCA B C is inscribed in a circle ω\omega. A variable line ℓ\ell chosen parallel to BCB C meets segments ABA B, ACA C at points D,ED, E respectively, and meets ω\omega at points K,LK, L (where DD lies between KK and EE ). Circle γ1\gamma_{1} is tangent to the segments KDK D and BDB D and also tangent to ω\omega, while circle γ2\gamma_{2} is tangent to the segments LEL E and CEC E and also tangent to ω\omega. Determine the locus, as ℓ\ell varies, of the meeting point of the common inner tangents to γ1\gamma_{1} and γ2\gamma_{2}. (Russia) VASily Mokin & Fedor IvLev

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Day 2

Problem 4

  • Day 2

Given a positive integer n=∏i=1spiαin=\prod_{i=1}^{s} p_{i}^{\alpha_{i}}, we write Ω(n)\Omega(n) for the total number ∑i=1sαi\sum_{i=1}^{s} \alpha_{i} of prime factors of nn, counted with multiplicity. Let λ(n)=(−1)Ω(n)\lambda(n)=(-1)^{\Omega(n)} (so, for example, λ(12)=λ(22⋅31)=(−1)2+1=−1)\left.\lambda(12)=\lambda\left(2^{2} \cdot 3^{1}\right)=(-1)^{2+1}=-1\right).

Prove the following two claims: i) There are infinitely many positive integers nn such that λ(n)=λ(n+1)=+1;\lambda(n)=\lambda(n+1)=+1 ; ii) There are infinitely many positive integers nn such that λ(n)=λ(n+1)=−1\lambda(n)=\lambda(n+1)=-1. (ROMANIA) DAN SchwARZ

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Problem 5

  • Day 2

For every n≥3n \geq 3, determine all the configurations of nn distinct points X1,X2,…,XnX_{1}, X_{2}, \ldots, X_{n} in the plane, with the property that for any pair of distinct points Xi,XjX_{i}, X_{j} there exists a permutation σ\sigma of the integers {1,…,n}\{1, \ldots, n\}, such that d(Xi,Xk)=d(Xj,Xσ(k))\mathrm{d}\left(X_{i}, X_{k}\right)=\mathrm{d}\left(X_{j}, X_{\sigma(k)}\right) for all 1≤k≤n1 \leq k \leq n. (We write d(X,Y)\mathrm{d}(X, Y) to denote the distance between points XX and YY.) (United Kingdom) LuKe BetTs

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Problem 6

  • Day 2
  • Answer

The cells of a square 2011×20112011 \times 2011 array are labelled with the integers 1,2,…,201121,2, \ldots, 2011^{2}, in such a way that every label is used exactly once. We then identify the lefthand and right-hand edges, and then the top and bottom, in the normal way to form a torus (the surface of a doughnut).

Determine the largest positive integer MM such that, no matter which labelling we choose, there exist two neighbouring cells with the difference of their labels at least M.[4] (ROMANIA) DAN SchwarZ Preamble. For a planar N×NN \times N array, it is folklore that this value is M=NM=N, with some easy models shown below. As such, the problem is mentioned in [Béla Bollobás - The Art of Mathematics], 21. Neighbours in a Matrix.

This is not necessarily a flaw on the actual problem, which is presented in a brand novel setting; on the contrary, some general previous knowledge on such type of problems (which we think must be encouraged) is beneficial in searching for the right ideas of a proof.

The idea for a proof goes along the lines of finding a moment in the consecutive filling with numbers of the array, when there are at least NN pairs of adjacent filled/yet-unfilled cells (with either distinct filled cells or distinct yet-unfilled cells). Then, when the cell next to that bearing the least label is filled, the difference between its label and the one being filled will be at least NN.

1 2 …\ldots N
 N+1\mathrm{~N}+1  N+2\mathrm{~N}+2 …\ldots 2 N
⋮\vdots ⋮\vdots ⋱\ddots ⋮\vdots
( N−1)N+1(\mathrm{~N}-1) \mathrm{N}+1 ( N−1)N+2(\mathrm{~N}-1) \mathrm{N}+2 …\ldots  N2\mathrm{~N}^{2}

A planar parallel N×NN \times N model array.

1 2 4 …\ldots  N( N−1)/2+1\mathrm{~N}(\mathrm{~N}-1) / 2+1
3 5 …\ldots  N( N−1)/2+2\mathrm{~N}(\mathrm{~N}-1) / 2+2
6 …\ldots
⋮\vdots ⋮\vdots ⋮\vdots ⋱\ddots ⋮\vdots ⋮\vdots
 N( N+1)/2−1\mathrm{~N}(\mathrm{~N}+1) / 2-1 …\ldots  N2−2\mathrm{~N}^{2}-2
 N( N+1)/2\mathrm{~N}(\mathrm{~N}+1) / 2 …\ldots  N2−1\mathrm{~N}^{2}-1  N2\mathrm{~N}^{2}

A planar diagonal N×NN \times N model array.

Answer, solutions and source